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Locomotive Engine
How much tunes you hear how a locomotive can pull if u know it is the tensile stress?
Is there a formula or conversion that with the figure given tractive effort you can discover how many barrels of a train can pull the engine?
Odd ... I understand the question well. As with all things railroad, and there are many variables, it depends. Here we go: The narrative of the story is actually on the train project, including coupler knuckle. There are many types of art vary in design and tensile strength of a type to type. High capacity draft gear is usually found in cars of trains unit, grain and coal in particular. While I worked "standard" E-Type (which should be the reference, right?) The art was understood that the draft be billed to 240,000 pounds. This figure includes a margin of 10,000 pounds for the error. If you have mixed loads, lower number is better to 240,000 pounds. if you want any kind of guarantee to keep the train in one piece. (Note: "F" type knuckles are almost the same score, but a fool goes into the drawbar in a hurry) But even though this figure may vary between standard and top speed capacity of project, the point is moot and the information is useless unless someone knows what do with it. So the question is: "How do we know how much force is exerted on the art project by the tonnage for the train that we have and the territory will move to the other side? "Someone much smarter than you and me with a very sharp pencil came up with the" Rolling Resistance Formula Train and "Train From Resistance Formula." The two are almost the same and pretty simple to understand. formula rolling resistance of the train is at: 20 pounds For each ton in the train, multiplied by the degree, plus 5 equals the tractive force, or [(20 x T) x% G] + 5 = F. Since force is the same except replace "30" in place of £ 20. Ok. I have 6,000 tons I need to get a grade of 2.5%. 20 x 6000 = 120 000 x 2.5 = 300,000 + 5 = 300,005 pounds. Oops. We above the limit of 60,005 pounds (300005-240000 = 60 005). What now? You must reduce the force the art project. You do that by reducing tonnage (rarely happens) or add helper power, whether open or DPU, pushing some of that excess final tonnage, reducing draft forces at the end of the head. When speaking of an assistant of several units with three units and up, and dragged (usually two units can go behind the last car, but certain restrictions may prohibit the placement), the assistant should be positioned so that the tonnage of aid mango, 1 / 3 of tonnage should be ahead of the final 2/3s aid. If you does the opposite, the aid can push the cars ahead of him on the right track. This creates the "node". The node is where the train where there is slack neutral. It say, the car being pulled last road engine and the first assistant coach of the court, "floating" if desired. The node may vary according to changes speed or grade as well as adjustments resulting from or loose. Speed is crucial for diesel electric locomotives so it must be figured in either operations or keeping a schedule. The latter is why pigs tend to have much power. The first is for planning. In short, the slower you go, the higher amperage going to traction engines. At about 12 mph and below, enter the diesel electric "short time", for which there is qualifying. This varies a little crazy from the model of the model, but once in a short time, you can only run the traction motors for so long before they are burned, or cable that feeds the fire. If you reached the maximum rating in the short period of time, the train must stop and let everything cool. And you know what? It takes reeeeeeeeeeeeeeaallllyyy long time to cool, so this should be avoided. The formula here is, horsepower per tonne (HPT just horsepower divided per ton) multiplied by 12, divided by the percentage rating is equal to the speed. Or, HPT x 12 /% G = speed. With the two formulas together is like one to quantify the amount of energy a given tonnage will need to achieve selection parameters and over a certain district. Thus we say the total amount HP is needed and how power is distributed on the train as necessary. Our 6,000 tons run of cases, our goal at speed of 15 mph. Say we have 18 000 HP. This is equivalent to three HPT. 3 x 12 / 2.5 = 14.4. Close enough. Assuming modest boobies 3000 horsepower, two would be the subject and the other would be an assistant single unit at the end of the train. (Actually, it is likely there are already three units at the tip, so I stick one in the rear of the train, as needed to reduce late head forces where needed.) Presto! Now you know more than any head on ...
